Question & Answer: 5.6 Warm up: Parsing strings (Java)…..

5.6.1: warm up: parsing strings (java)

5.6 Warm up: Parsing strings (Java)

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Question & Answer: 5.6 Warm up: Parsing strings (Java)…..
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(1) Prompt the user for a string that contains two strings separated by a comma. (1 pt)

Examples of strings that can be accepted:

Jill, Allen

Jill , Allen

Jill,Allen

Ex:

lab submission 5.6 1 warm up parsing strings java

Enter input string: Jill, Allen

(2) Report an error if the input string does not contain a comma. Continue to prompt until a valid string is entered. Note: If the input contains a comma, then assume that the input also contains two strings. (2 pts)

Ex:

Enter input string: Jill Allen
Error: No comma in string
Enter input string: Jill, Allen

(3) Extract the two words from the input string and remove any spaces. Store the strings in two separate variables and output the strings. (2 pts)

Ex:

Enter input string: Jill, Allen
First word: Jill
Second word: Allen

(4) Using a loop, extend the program to handle multiple lines of input. Continue until the user enters q to quit. (2 pts)

Ex:

Enter input string: Jill, Allen
First word: Jill
Second word: Allen


Enter input string: Golden , Monkey
First word: Golden
Second word: Monkey


Enter input string: Washington,DC
First word: Washington
Second word: DC


Enter input string: q
lab submission 5.6 1 warm up parsing strings java

Expert Answer

5.6.1: warm up: parsing strings (java)

Tested on Eclipse with Java-8

package stringclass;

import java.util.Scanner;

// TODO: Auto-generated Javadoc

/**

* The Class ParsingString.

* @author Lalchand Mali.

*/

public class ParsingString {

/**

* The main method.

*

* @param args the arguments

*/

public static void main(String[] args) {

String userInput;

Scanner input = new Scanner(System.in);

/**

* Taking input from user

*/

System.out.print(“Enter input string: “);

userInput = input.nextLine();

/**

* Loop continue until userInput not equal to q

*/

while(!userInput.equals(“q”)) {

/**

* If input contain comm then split it

* otherwise print error with message

* and continue for user input

*/

if(userInput.contains(“,”)){

String[] arr = userInput.split(“,”);

System.out.println(“First Word:” + arr[0].trim());

System.out.println(“Second Word:” + arr[1].trim());

} else{

System.out.println(“Error: No comma in string”);

}

System.out.print(“Enter input string: “);

userInput = input.nextLine();

}

/**

* closing Scanner stream.

*/

if(input!=null){

input.close();

}

}

}

/**************************Output***************************/

Enter input string: Jill Allen
Error: No comma in string
Enter input string: Jill, Allen
First Word:Jill
Second Word:Allen
Enter input string: Golden , Monkey
First Word:Golden
Second Word:Monkey
Enter input string: Washington,DC
First Word:Washington
Second Word:DC
Enter input string: q

5.6.1: warm up: parsing strings (java)

lab submission 5.6 1 warm up parsing strings java

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