MTH122 MOD3 Peer discussion Response 200 words each

I’m trying to learn for my Algebra class and I’m stuck. Can you help?

Please respond to both POST1: and POST2: in at least 200 words each.

Initial post that both POST1: and POST2: are responding to.

Consider the following two functions:

• F(m): The average temperature in Fahrenheit during month (m) of the year.

• C(f): The conversion formula to calculate the temperature in Celsius based on the temperature in Fahrenheit (f).

For this discussion, your task is as follows:

• Calculate (C ? F) for the month of your choice.
• Discuss the meaning of the function (C ? F)(m).
• How does the composition of functions in parts (a) and (b) compare to (F ? C)(m)? Are they the same?

POST1:

Hello Class,

The month I will use to calculate will be F(August)=84.

In this example we are using two known functions to produce desired outputs. These are functions because for every input there is only one output.

a) C(F)=5/9*(F-32)= C(84)=5/9*(84-32)= 28.89

b) (C ? F)(m) is used to describe the function that converts F(m) from a average temperature in Fahrenheit to an average temperature in Celsius. In the above example F(August)=84 so we can substitute the value of F to find an equivalent output in Celsius.

c) (F ?C)(m) would be used to convert the Average temperature in Celsius to Average temperature in Fahrenheit. This conversion would need a known value of C(m). That value would be an input into the function F(C).

POST2:

For this example, I chose to calculate by birth month of February averaging 43 degrees Fahrenheit. Using c(f) = 5/9 (f-32)

A) The temperature in Celsius is calculated as:

c(43) = 5/9 (43-32)

=5/9(11)

=6.1 degrees Celsius

B) The function (C ? F)(m) is to take the average temperature, in Fahrenheit, from the months in a year and convert this into Celsius.

C) (C ? F) (m) would be different from (F ? C) (m). While (C ? F) (m) gives the average temperature of a particular month in Celsius, (F ? C) (m) converts visa versa.