[SOLVED] Program – c++

I’m trying to learn for my Programming class and I’m stuck. Can you help?

For this program you will use a genetic algorithm to solve a small example of a real-world problem.

Consider the problem of producing a university class schedule. Each course must be taught. It must have a room, and a time. Only one course can be taught in a room at a time. The room must be able to hold the expected number of students. It must have an instructor. Each instructor can teach any of several courses, but only those courses, and there is an upper limit on how many courses one instructor can teach. Finally, we may have additional preferences regarding scheduling; for example, if there are courses that are usually taken the same semester, we would prefer (but not require) that they be taught in adjacent time slots, and if they’re in adjacent time slots, that they be in rooms that are close together.

You are given a list of 12 courses. (Some of these may be multiple sections of the same course, but that doesn’t affect our problem here.) You also have a list of several faculty members, and the courses each can teach. You also have a list of available rooms and time slots. Your task is to use a genetic algorithm to devise a suitable teaching schedule.

In a production system, we’d probably want the program to read the various options (courses, instructors, etc) from input files, but for this assignment you can use input files or put the data directly into your source code.

Courses and expected enrollments are: CS 101A (40), CS 101B (25), CS 201A (30), CS 201B (30), CS 191A (60), CS 191B (20), CS 291B (40), CS 291A (20), CS 303 (50), CS 341 (40), CS 449 (55), CS 461 (40).

Instructors and what they can teach:

• Hare: CS 101, CS 201, CS 291, CS 303, CS 449, CS 461
• Bingham: CS 101, CS 201, CS 191, CS 291, CS 449
• Kuhail: CS 303, CS 341
• Mitchell: CS 191, CS 291, CS 303, CS 341
• Rao: CS 291, CS 303, CS 341, CS 461

Time slots: 10A, 11A, 12P, 1P, 2P, 3P, 4P (We’re assuming these are all MWF courses)

Rooms and capacities: Haag 301 (70), Haag 206 (30), Royall 204 (70), Katz 209 (50), Flarsheim 310 (80), Flarsheim 260 (25), Bloch 0009 (30)

Fitness function:

Assign instructors, times, rooms, and courses. For your initial population, this will be random. Assess the fitness function as follows:

• For each course that is taught by an instructor who can teach it: +3
• For each course that is the only course scheduled in that room at that time: +5
• For each course that is in a room large enough to accommodate it: +5
  • Room capacity is no more than twice the expected enrollment: +2
• For each course that does not have the same instructor teaching another course at the same time: +5
• For each schedule that has the same instructor teaching more than 4 courses: -5 per course over 4
• For each schedule that has Rao or Mitchell (graduate faculty) teaching more courses than Hare or Bingham: -5% to total fitness score. (Same number of courses is OK.)
• CS 101 and CS 191 are usually taken the same semester; the same applies to CS 201 and CS 291. Therefore apply these rules to those pairs of courses:
  • Courses are scheduled for same time: -10% to score
  • Courses are scheduled for adjacent times: +5% to score
  • if these courses are scheduled for adjacent times, and
    • Are in the same building: +5 points
    • Are both on the quad (Haag, Royall, Flarsheim): no modification
    • 1 is in Katz and the other isn’t: -3%
      1 is in Bloch and the other isn’t: -3%
      (Yes, if one’s in Katz and the other’s in Bloch, that’s -6%)

Selection for breeding: Use L2 normalization. If any schedule has a net score less than 0, treat it as 0.

Crossover/mutation: It’ll probably be simplest to assign each course its own column in a table,which will not change, and then select sections of table (i.e. columns) for the crossover section. Select a random (uniform) division point to make the split, with at least 1 column from each table surviving to the next generation. For mutation, give each table entry a small probability–0.01 or so, no more than 0.05–of being replaced with a randomly-selected element from that population (rooms, instructors, etc).

Report the average fitness and best fitness of each generation, until the best fitness in the population increases by less than 0.2% for 3 consecutive generations. Report the best schedule you find. Your program should report any constraints that are violated (multiple courses in the same room, too many courses by 1 instructor, etc.) The room preferences for CS 101/191 and CS 201/291 are just that—preferences–so it’s OK if they’re violated. (Better if they’re not, but the fitness function will take care of that.)

Extra credit: For 5 points (half a letter grade) extra credit, implement any 2 additional features for the fitness function. Perhaps some instructors have a room or building preference, or morning/afternoon, or prefer a break between classes, or are OK with 2 classes back-to-back but not 3 or more, or have health issues that make walking over to Katz or Bloch significantly difficult, or different sections of the same course not taught too close together in time, or…whatever.

You may write your program in C, C++, C#, Java, or Python. (If you’ve got something else you want to use, talk to me, we’ll discuss it.) Submit your program source code, and a sample program run with the schedule it produces. Also write up a short report discussing your program, what data structures you used, what additional rules you added (if you went for the extra credit), or ideas for how this program could be extended or generalized.

Due Sunday night, September 29 (Upload link vanishes 8 AM Monday, Sep 30).

Appendix: example of L2 normalization

Suppose we have 5 possible schedules with the following scores:

S1: 55

S2: 20

S3: 17

S4: 42

S5: -2 (which will become 0)

Find the square of each:

S1: 3025

S2: 400

S3: 289

S4: 1764

S5: 0

Now divide by the sum of squares (rounded here to 3 decimal places):

SS = 5478

S1 = 3025 / 5478 = 0.552

S2 = 400 / 5478 = 0.073

S3 = 289 / 5478 = 0.053

S4 = 1764 / 5478 = 0.322

S5 = 0 / 5478 = 0

Now find the cumulative distribution:

S1: 0.552

S2: 0.552 + 0.073 = 0.625

S3: 0.625 + 0.053 = 0.678

S4: 0.678 + 0.322 = 1.000

Note that S5 has dropped out (probability 0).

Generate a uniform random number in [0, 1] to select an item based on what range it falls into.

j = random();  
idx = 0; 
while table[idx] < j
       idx++;

Of course, your population will be much larger, at least 200 or so, so the range will be smaller for each item.

Prepare a short (1 Page) report explaining your program and the algorithm you chose, and how well it worked. How well would your solution scale up to a larger board?